A computer algebra system written in pure Python http://sympy.org/ . To get started to with contributing https://github.com/sympy/sympy/wiki/Introduction-to-contributing
smichr on master
NotIterable has new home iterable != Expr There is no n… don't put None in Tuple and 6 more (compare)
replace
with a pattern.
>>> a, b, c = Wild('a'), Wild('b'), Wild('c')
>>> expr.replace((a**b)**c, a**(b*c))
y
integrate(Heaviside(x,0), (x,-1,1) =1
, but instead sympy returns Integral(Heaviside(x, 0), (x, -1, 1))
. Works fine if I omit the second argument of Heaviside
, but I think it should work in any case, as the value at x=0
is irrelevant for the integration (set of measure zero).
@laolux:privacytools.io Many integrators like meijerint
work by looking up the results in a table. The table may contain Heaviside(x)
but not Heaviside(x, 0)
which is a different object.
>>> Heaviside(x) == Heaviside(x, 0)
False
It may be possible to extend the matching code to handle this but that may not be easy to implement. Another entry should probably be added.
I ran into the following issue/error while trying to get the extrema of a simple 4th order polynomial:
import sympy as sym
x_sym = sym.symbols("x", real=True) # single variable
pot_sym = x_sym**4 - x_sym**2 + x_sym * 1/10 # function f
pot_prime_sym = sym.diff(pot_sym, x_sym) # first derivative of function df/fx
extrema = sym.solve(pot_prime_sym) # get extrema via df/dx == 0
for extremum in extrema:
print(sym.N(extremum), " == ", sym.N(sym.simplify(extremum))) # print values
returns:
0.050253826762553 - 0.e-23*I == 0.050253826762553 + 3.70576914423756e-22*I
0.680639276423668 + 0.e-23*I == 0.680639276423668
-0.730893103186221 + 0.e-23*I == -0.730893103186221
The last two results are equal, but the first entry does seem to cause an error of I simplify the result before returning its numeric value. There should be no complex contribution 3.7e-22*I
, thus something goes wrong here.
Is this a know issue, did I do something wrong, or is this a not-yet know issue and I should open a issue on github?
I am using sympy 1.7.1
.
convert_to(expr, system._base_units)
and then xreplace the base units
print(type(curl(H, doit=False)))
H
is an Add
object whose arguments are Mul
objects, not a vector.In [10]: srepr(H)
Out[10]: "Add(Mul(T.x, Function('Hx')(Symbol('x'), Symbol('y'), Symbol('z'))), Mul(T.y, Function('Hy')(Symbol('x'), Symbol('y'), Symbol('z'))), Mul(T.z, Function('Hz')(Symbol('x'), Symbol('y'), Symbol('z'))))"
Hi, I'd like to express a vector norm with indexed variables for differentation, but I don't quite know how. Every search I came up with led to matrix norms, which aren't really in question here. The variables are indeed vectors, but I don't care about the dimensionality in this case. Formulating a difference is easy enough, but I'm not sure how to continue.
# || x_a - y_b ||
x = sp.IndexedBase('x')
a = sp.Idx('a')
y = sp.IndexedBase('y')
b = sp.Idx('b')
diff = (x[a] - y[b])
How could this be achieved? I'm open for any other formulations as well! Much appreciated.